-5(3y-8)-y=-2(y-5)

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Solution for -5(3y-8)-y=-2(y-5) equation: 



-5(3y-8)-y=-2(y-5)

We move all terms to the left:

-5(3y-8)-y-(-2(y-5))=0

We add all the numbers together, and all the variables

-1y-5(3y-8)-(-2(y-5))=0

We multiply parentheses

-1y-15y-(-2(y-5))+40=0



We calculate terms in parentheses: -(-2(y-5)), so:

-2(y-5)

We multiply parentheses

-2y+10

Back to the equation:

-(-2y+10)



We add all the numbers together, and all the variables

-16y-(-2y+10)+40=0

We get rid of parentheses

-16y+2y-10+40=0

We add all the numbers together, and all the variables

-14y+30=0

We move all terms containing y to the left, all other terms to the right

-14y=-30

y=-30/-14

y=2+1/7

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