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180=w(2w-9)
We move all terms to the left:
180-(w(2w-9))=0
We calculate terms in parentheses: -(w(2w-9)), so:We get rid of parentheses
w(2w-9)
We multiply parentheses
2w^2-9w
Back to the equation:
-(2w^2-9w)
-2w^2+9w+180=0
a = -2; b = 9; c = +180;
Δ = b2-4ac
Δ = 92-4·(-2)·180
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-39}{2*-2}=\frac{-48}{-4} =+12 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+39}{2*-2}=\frac{30}{-4} =-7+1/2 $
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