90-2x=(180-x)/5

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Solution for 90-2x=(180-x)/5 equation:



90-2x=(180-x)/5
We move all terms to the left:
90-2x-((180-x)/5)=0
We add all the numbers together, and all the variables
-2x-((-1x+180)/5)+90=0
We multiply all the terms by the denominator
-2x*5)-((-1x+180)+90*5)=0
We add all the numbers together, and all the variables
-2x*5)-((-1x+180)=0
Wy multiply elements
-10x^2=0
a = -10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-10)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-20}=0$

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