180=68+(10x-40)+(9x-19)

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Solution for 180=68+(10x-40)+(9x-19) equation: 



180=68+(10x-40)+(9x-19)

We move all terms to the left:

180-(68+(10x-40)+(9x-19))=0



We calculate terms in parentheses: -(68+(10x-40)+(9x-19)), so:

68+(10x-40)+(9x-19)

determiningTheFunctionDomain
(10x-40)+(9x-19)+68

We get rid of parentheses

10x+9x-40-19+68

We add all the numbers together, and all the variables

19x+9

Back to the equation:

-(19x+9)



We get rid of parentheses

-19x-9+180=0

We add all the numbers together, and all the variables

-19x+171=0

We move all terms containing x to the left, all other terms to the right

-19x=-171

x=-171/-19

x=+9

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