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180=2/5x+2x
We move all terms to the left:
180-(2/5x+2x)=0
Domain of the equation: 5x+2x)!=0We add all the numbers together, and all the variables
x∈R
-(+2x+2/5x)+180=0
We get rid of parentheses
-2x-2/5x+180=0
We multiply all the terms by the denominator
-2x*5x+180*5x-2=0
Wy multiply elements
-10x^2+900x-2=0
a = -10; b = 900; c = -2;
Δ = b2-4ac
Δ = 9002-4·(-10)·(-2)
Δ = 809920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{809920}=\sqrt{64*12655}=\sqrt{64}*\sqrt{12655}=8\sqrt{12655}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(900)-8\sqrt{12655}}{2*-10}=\frac{-900-8\sqrt{12655}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(900)+8\sqrt{12655}}{2*-10}=\frac{-900+8\sqrt{12655}}{-20} $
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