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1/5x-5/x=5
We move all terms to the left:
1/5x-5/x-(5)=0
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: x!=0We calculate fractions
x∈R
x/5x^2+(-25x)/5x^2-5=0
We multiply all the terms by the denominator
x+(-25x)-5*5x^2=0
Wy multiply elements
-25x^2+x+(-25x)=0
We get rid of parentheses
-25x^2+x-25x=0
We add all the numbers together, and all the variables
-25x^2-24x=0
a = -25; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·(-25)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*-25}=\frac{0}{-50} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*-25}=\frac{48}{-50} =-24/25 $
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