180=(47-2x)+(10x-7)+(7x-10)

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Solution for 180=(47-2x)+(10x-7)+(7x-10) equation: 



180=(47-2x)+(10x-7)+(7x-10)

We move all terms to the left:

180-((47-2x)+(10x-7)+(7x-10))=0

We add all the numbers together, and all the variables

-((-2x+47)+(10x-7)+(7x-10))+180=0



We calculate terms in parentheses: -((-2x+47)+(10x-7)+(7x-10)), so:

(-2x+47)+(10x-7)+(7x-10)

We get rid of parentheses

-2x+10x+7x+47-7-10

We add all the numbers together, and all the variables

15x+30

Back to the equation:

-(15x+30)



We get rid of parentheses

-15x-30+180=0

We add all the numbers together, and all the variables

-15x+150=0

We move all terms containing x to the left, all other terms to the right

-15x=-150

x=-150/-15

x=+10

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