(n+4)/10=(n-8)/2

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Solution for (n+4)/10=(n-8)/2 equation: 



(n+4)/10=(n-8)/2

We move all terms to the left:

(n+4)/10-((n-8)/2)=0

We calculate fractions


n/()+(-((n-8)*10)/()=0



We calculate terms in parentheses: +(-((n-8)*10)/(), so:

-((n-8)*10)/(

We multiply all the terms by the denominator


-((n-8)*10)



We calculate terms in parentheses: -((n-8)*10), so:

(n-8)*10

We multiply parentheses

10n-80

Back to the equation:

-(10n-80)



We get rid of parentheses

-10n+80

Back to the equation:

+(-10n+80)



We get rid of parentheses

n/()-10n+80=0

We multiply all the terms by the denominator


n-10n*()+80*()=0

We add all the numbers together, and all the variables

n-10n*()=0

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