180=(11x-30)(5x+2)

Solution for 180=(11x-30)(5x+2) equation:

180=(11x-30)(5x+2)

We move all terms to the left:

180-((11x-30)(5x+2))=0

We multiply parentheses ..

-((+55x^2+22x-150x-60))+180=0


We calculate terms in parentheses: -((+55x^2+22x-150x-60)), so:

(+55x^2+22x-150x-60)

We get rid of parentheses

55x^2+22x-150x-60

We add all the numbers together, and all the variables

55x^2-128x-60

Back to the equation:

-(55x^2-128x-60)


We get rid of parentheses

-55x^2+128x+60+180=0

We add all the numbers together, and all the variables

-55x^2+128x+240=0

a = -55; b = 128; c = +240;
Δ = b2-4ac
Δ = 1282-4·(-55)·240
Δ = 69184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{69184}=\sqrt{64*1081}=\sqrt{64}*\sqrt{1081}=8\sqrt{1081}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(128)-8\sqrt{1081}}{2*-55}=\frac{-128-8\sqrt{1081}}{-110}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(128)+8\sqrt{1081}}{2*-55}=\frac{-128+8\sqrt{1081}}{-110}
$