180=(6x+1)(x+4)

Solution for 180=(6x+1)(x+4) equation:

180=(6x+1)(x+4)

We move all terms to the left:

180-((6x+1)(x+4))=0

We multiply parentheses ..

-((+6x^2+24x+x+4))+180=0


We calculate terms in parentheses: -((+6x^2+24x+x+4)), so:

(+6x^2+24x+x+4)

We get rid of parentheses

6x^2+24x+x+4

We add all the numbers together, and all the variables

6x^2+25x+4

Back to the equation:

-(6x^2+25x+4)


We get rid of parentheses

-6x^2-25x-4+180=0

We add all the numbers together, and all the variables

-6x^2-25x+176=0

a = -6; b = -25; c = +176;
Δ = b2-4ac
Δ = -252-4·(-6)·176
Δ = 4849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{4849}}{2*-6}=\frac{25-\sqrt{4849}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{4849}}{2*-6}=\frac{25+\sqrt{4849}}{-12}
$