180=(10y+6)(8y-6)

Solution for 180=(10y+6)(8y-6) equation:

180=(10y+6)(8y-6)

We move all terms to the left:

180-((10y+6)(8y-6))=0

We multiply parentheses ..

-((+80y^2-60y+48y-36))+180=0


We calculate terms in parentheses: -((+80y^2-60y+48y-36)), so:

(+80y^2-60y+48y-36)

We get rid of parentheses

80y^2-60y+48y-36

We add all the numbers together, and all the variables

80y^2-12y-36

Back to the equation:

-(80y^2-12y-36)


We get rid of parentheses

-80y^2+12y+36+180=0

We add all the numbers together, and all the variables

-80y^2+12y+216=0

a = -80; b = 12; c = +216;
Δ = b2-4ac
Δ = 122-4·(-80)·216
Δ = 69264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{69264}=\sqrt{144*481}=\sqrt{144}*\sqrt{481}=12\sqrt{481}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12\sqrt{481}}{2*-80}=\frac{-12-12\sqrt{481}}{-160}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12\sqrt{481}}{2*-80}=\frac{-12+12\sqrt{481}}{-160}
$