10+4x=5(x-5)+33

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Solution for 10+4x=5(x-5)+33 equation: 



10+4x=5(x-5)+33

We move all terms to the left:

10+4x-(5(x-5)+33)=0



We calculate terms in parentheses: -(5(x-5)+33), so:

5(x-5)+33

We multiply parentheses

5x-25+33

We add all the numbers together, and all the variables

5x+8

Back to the equation:

-(5x+8)



We get rid of parentheses

4x-5x-8+10=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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