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180(n-2)n=25
We move all terms to the left:
180(n-2)n-(25)=0
We multiply parentheses
180n^2-360n-25=0
a = 180; b = -360; c = -25;
Δ = b2-4ac
Δ = -3602-4·180·(-25)
Δ = 147600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{147600}=\sqrt{3600*41}=\sqrt{3600}*\sqrt{41}=60\sqrt{41}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-360)-60\sqrt{41}}{2*180}=\frac{360-60\sqrt{41}}{360} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-360)+60\sqrt{41}}{2*180}=\frac{360+60\sqrt{41}}{360} $
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