18-6(9x-2)=17(x-3)+15(13-x)-50

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Solution for 18-6(9x-2)=17(x-3)+15(13-x)-50 equation: 



18-6(9x-2)=17(x-3)+15(13-x)-50

We move all terms to the left:

18-6(9x-2)-(17(x-3)+15(13-x)-50)=0

We add all the numbers together, and all the variables

-6(9x-2)-(17(x-3)+15(-1x+13)-50)+18=0

We multiply parentheses

-54x-(17(x-3)+15(-1x+13)-50)+12+18=0



We calculate terms in parentheses: -(17(x-3)+15(-1x+13)-50), so:

17(x-3)+15(-1x+13)-50

We multiply parentheses

17x-15x-51+195-50

We add all the numbers together, and all the variables

2x+94

Back to the equation:

-(2x+94)



We add all the numbers together, and all the variables

-54x-(2x+94)+30=0

We get rid of parentheses

-54x-2x-94+30=0

We add all the numbers together, and all the variables

-56x-64=0

We move all terms containing x to the left, all other terms to the right

-56x=64

x=64/-56

x=-1+1/7

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