3n-(4-(5+3n))=((3n-7)-4)-(n+1)

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Solution for 3n-(4-(5+3n))=((3n-7)-4)-(n+1) equation: 



3n-(4-(5+3n))=((3n-7)-4)-(n+1)

We move all terms to the left:

3n-(4-(5+3n))-(((3n-7)-4)-(n+1))=0

We add all the numbers together, and all the variables

3n-(4-(3n+5))-(((3n-7)-4)-(n+1))=0



We calculate terms in parentheses: -(4-(3n+5)), so:

4-(3n+5)

determiningTheFunctionDomain
-(3n+5)+4

We get rid of parentheses

-3n-5+4

We add all the numbers together, and all the variables

-3n-1

Back to the equation:

-(-3n-1)





We calculate terms in parentheses: -(((3n-7)-4)-(n+1)), so:

((3n-7)-4)-(n+1)

We get rid of parentheses

((3n-7)-4)-n-1



We calculate terms in parentheses: +((3n-7)-4), so:

(3n-7)-4

We get rid of parentheses

3n-7-4

We add all the numbers together, and all the variables

3n-11

Back to the equation:

+(3n-11)



We add all the numbers together, and all the variables

-1n+(3n-11)-1

We get rid of parentheses

-1n+3n-11-1

We add all the numbers together, and all the variables

2n-12

Back to the equation:

-(2n-12)



We get rid of parentheses

3n+3n-2n+1+12=0

We add all the numbers together, and all the variables

4n+13=0

We move all terms containing n to the left, all other terms to the right

4n=-13

n=-13/4

n=-3+1/4

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