18(2x+12)+12(6-7x)=10(44-2x)-7(x+13)+3

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Solution for 18(2x+12)+12(6-7x)=10(44-2x)-7(x+13)+3 equation: 



18(2x+12)+12(6-7x)=10(44-2x)-7(x+13)+3

We move all terms to the left:

18(2x+12)+12(6-7x)-(10(44-2x)-7(x+13)+3)=0

We add all the numbers together, and all the variables

18(2x+12)+12(-7x+6)-(10(-2x+44)-7(x+13)+3)=0

We multiply parentheses

36x-84x-(10(-2x+44)-7(x+13)+3)+216+72=0



We calculate terms in parentheses: -(10(-2x+44)-7(x+13)+3), so:

10(-2x+44)-7(x+13)+3

We multiply parentheses

-20x-7x+440-91+3

We add all the numbers together, and all the variables

-27x+352

Back to the equation:

-(-27x+352)



We add all the numbers together, and all the variables

-48x-(-27x+352)+288=0

We get rid of parentheses

-48x+27x-352+288=0

We add all the numbers together, and all the variables

-21x-64=0

We move all terms containing x to the left, all other terms to the right

-21x=64

x=64/-21

x=-3+1/21

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