3(x+2)=9(2+x)

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Solution for 3(x+2)=9(2+x) equation: 



3(x+2)=9(2+x)

We move all terms to the left:

3(x+2)-(9(2+x))=0

We add all the numbers together, and all the variables

3(x+2)-(9(x+2))=0

We multiply parentheses

3x-(9(x+2))+6=0



We calculate terms in parentheses: -(9(x+2)), so:

9(x+2)

We multiply parentheses

9x+18

Back to the equation:

-(9x+18)



We get rid of parentheses

3x-9x-18+6=0

We add all the numbers together, and all the variables

-6x-12=0

We move all terms containing x to the left, all other terms to the right

-6x=12

x=12/-6

x=-2

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