18(1/9(3t-6))=(t+16/18)18

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Solution for 18(1/9(3t-6))=(t+16/18)18 equation: 



18(1/9(3t-6))=(t+16/18)18

We move all terms to the left:

18(1/9(3t-6))-((t+16/18)18)=0



Domain of the equation: 9(3t-6))!=0

t∈R



We add all the numbers together, and all the variables

18(1/9(3t-6))-((+t+16/18)18)=0

We calculate fractions

We do not support etpression: t^3

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