5a-a(a-3)=7

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Solution for 5a-a(a-3)=7 equation:



5a-a(a-3)=7
We move all terms to the left:
5a-a(a-3)-(7)=0
We multiply parentheses
-a^2+5a+3a-7=0
We add all the numbers together, and all the variables
-1a^2+8a-7=0
a = -1; b = 8; c = -7;
Δ = b2-4ac
Δ = 82-4·(-1)·(-7)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-6}{2*-1}=\frac{-14}{-2} =+7 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+6}{2*-1}=\frac{-2}{-2} =1 $

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