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17x^2=49
We move all terms to the left:
17x^2-(49)=0
a = 17; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·17·(-49)
Δ = 3332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3332}=\sqrt{196*17}=\sqrt{196}*\sqrt{17}=14\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{17}}{2*17}=\frac{0-14\sqrt{17}}{34} =-\frac{14\sqrt{17}}{34} =-\frac{7\sqrt{17}}{17} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{17}}{2*17}=\frac{0+14\sqrt{17}}{34} =\frac{14\sqrt{17}}{34} =\frac{7\sqrt{17}}{17} $
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