p+(p+3)+(p-4)=20

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Solution for p+(p+3)+(p-4)=20 equation: 



p+(p+3)+(p-4)=20

We move all terms to the left:

p+(p+3)+(p-4)-(20)=0

We get rid of parentheses

p+p+p+3-4-20=0

We add all the numbers together, and all the variables

3p-21=0

We move all terms containing p to the left, all other terms to the right

3p=21

p=21/3

p=7

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