If it's not what You are looking for type in the equation solver your own equation and let us solve it.
17p^2=170
We move all terms to the left:
17p^2-(170)=0
a = 17; b = 0; c = -170;
Δ = b2-4ac
Δ = 02-4·17·(-170)
Δ = 11560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11560}=\sqrt{1156*10}=\sqrt{1156}*\sqrt{10}=34\sqrt{10}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-34\sqrt{10}}{2*17}=\frac{0-34\sqrt{10}}{34} =-\frac{34\sqrt{10}}{34} =-\sqrt{10} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+34\sqrt{10}}{2*17}=\frac{0+34\sqrt{10}}{34} =\frac{34\sqrt{10}}{34} =\sqrt{10} $
| 3(2x+7)=7x-15 | | x=3.1415/16 | | 4p=-20+8p | | 2y-4*y=240 | | x=1.4÷0.7 | | -5x+10=3x+20 | | 8b=84 | | 84=2(3b+b) | | 22/60=x/100 | | 3/4(8x+12)=3 | | 14t-8=12t+20 | | -3(5s-8)=-6 | | 14=8-6x-8x | | 2(3x-5)=3(x-1) | | x^2+3x+62=0 | | 8m/3+4=12 | | 4.309+y=-4.3092 | | 1=2(-5-2b) | | 3/4+5p=3p-2 | | 4,039+y=-4,3092 | | 1/2=7/4x | | 0,2n+2=-3 | | 0,2n+2=−3 | | 6=3q/7 | | -2,3+2t=0,9 | | 45x+53x=1029 | | 2q-9-3q=-2+4 | | 3÷4+5p=3p-2 | | -7/6a+5=-6 | | ¾+5p=3p-2 | | 1+4n=-1 | | −1=1+4n |