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2(3x-5)=3(x-1)
We move all terms to the left:
2(3x-5)-(3(x-1))=0
We multiply parentheses
6x-(3(x-1))-10=0
We calculate terms in parentheses: -(3(x-1)), so:We get rid of parentheses
3(x-1)
We multiply parentheses
3x-3
Back to the equation:
-(3x-3)
6x-3x+3-10=0
We add all the numbers together, and all the variables
3x-7=0
We move all terms containing x to the left, all other terms to the right
3x=7
x=7/3
x=2+1/3
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