17c+5(3c-2)=7(-2c)-6(c-7)

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Solution for 17c+5(3c-2)=7(-2c)-6(c-7) equation: 



17c+5(3c-2)=7(-2c)-6(c-7)

We move all terms to the left:

17c+5(3c-2)-(7(-2c)-6(c-7))=0

We multiply parentheses

17c+15c-(7(-2c)-6(c-7))-10=0



We calculate terms in parentheses: -(7(-2c)-6(c-7)), so:

7(-2c)-6(c-7)

We multiply parentheses

-14c-6c+42

We add all the numbers together, and all the variables

-20c+42

Back to the equation:

-(-20c+42)



We add all the numbers together, and all the variables

32c-(-20c+42)-10=0

We get rid of parentheses

32c+20c-42-10=0

We add all the numbers together, and all the variables

52c-52=0

We move all terms containing c to the left, all other terms to the right

52c=52

c=52/52

c=1

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