2e+(e+3)=48

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Solution for 2e+(e+3)=48 equation: 



2e+(e+3)=48

We move all terms to the left:

2e+(e+3)-(48)=0

We get rid of parentheses

2e+e+3-48=0

We add all the numbers together, and all the variables

3e-45=0

We move all terms containing e to the left, all other terms to the right

3e=45

e=45/3

e=15

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