17b-b2=60

Solution for 17b-b2=60 equation:

17b-b2=60

We move all terms to the left:

17b-b2-(60)=0

We add all the numbers together, and all the variables

-1b^2+17b-60=0

a = -1; b = 17; c = -60;
Δ = b2-4ac
Δ = 172-4·(-1)·(-60)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-7}{2*-1}=\frac{-24}{-2}
=+12
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+7}{2*-1}=\frac{-10}{-2}
=+5
$