3(2c-7)=4c-39

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Solution for 3(2c-7)=4c-39 equation: 



3(2c-7)=4c-39

We move all terms to the left:

3(2c-7)-(4c-39)=0

We multiply parentheses

6c-(4c-39)-21=0

We get rid of parentheses

6c-4c+39-21=0

We add all the numbers together, and all the variables

2c+18=0

We move all terms containing c to the left, all other terms to the right

2c=-18

c=-18/2

c=-9

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