17=2(b+3)-3

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Solution for 17=2(b+3)-3 equation: 



17=2(b+3)-3

We move all terms to the left:

17-(2(b+3)-3)=0



We calculate terms in parentheses: -(2(b+3)-3), so:

2(b+3)-3

We multiply parentheses

2b+6-3

We add all the numbers together, and all the variables

2b+3

Back to the equation:

-(2b+3)



We get rid of parentheses

-2b-3+17=0

We add all the numbers together, and all the variables

-2b+14=0

We move all terms containing b to the left, all other terms to the right

-2b=-14

b=-14/-2

b=+7

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