3(y-4)=3y+3-3(-4-1)

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Solution for 3(y-4)=3y+3-3(-4-1) equation: 



3(y-4)=3y+3-3(-4-1)

We move all terms to the left:

3(y-4)-(3y+3-3(-4-1))=0

We add all the numbers together, and all the variables

3(y-4)-(3y+3-3(-5))=0

We multiply parentheses

3y-(3y+3-3(-5))-12=0



We calculate terms in parentheses: -(3y+3-3(-5)), so:

3y+3-3(-5)

We add all the numbers together, and all the variables

3y+18

Back to the equation:

-(3y+18)



We get rid of parentheses

3y-3y-18-12=0

We add all the numbers together, and all the variables

-30!=0

There is no solution for this equation

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