17=2(2K/4-3k)

Solution for 17=2(2K/4-3k) equation:

17=2(2/4-3K)

We move all terms to the left:

17-(2(2/4-3K))=0


Domain of the equation: 4-3K))!=0

We move all terms containing K to the left, all other terms to the right

-3K))!=-4

K!=-4/1

K!=-4

K∈R


We add all the numbers together, and all the variables

-(2(-3K+2/4))+17=0

We multiply all the terms by the denominator


-(2(-3K+2+17*4))=0


We calculate terms in parentheses: -(2(-3K+2+17*4)), so:

2(-3K+2+17*4)

We add all the numbers together, and all the variables

2(-3K+70)

We multiply parentheses

-6K+140

Back to the equation:

-(-6K+140)


We get rid of parentheses

6K-140=0

We move all terms containing K to the left, all other terms to the right

6K=140

K=140/6

K=23+1/3