17=1/3(9y+12)

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Solution for 17=1/3(9y+12) equation: 



17=1/3(9y+12)

We move all terms to the left:

17-(1/3(9y+12))=0



Domain of the equation: 3(9y+12))!=0

y∈R



We multiply all the terms by the denominator


-(1+17*3(9y+12))=0



We calculate terms in parentheses: -(1+17*3(9y+12)), so:

1+17*3(9y+12)

determiningTheFunctionDomain
17*3(9y+12)+1

Wy multiply elements

51y(9+1

Back to the equation:

-(51y(9+1)



We add all the numbers together, and all the variables

-(51y10=0

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