2(x+1)=6(x-3)-8

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Solution for 2(x+1)=6(x-3)-8 equation: 



2(x+1)=6(x-3)-8

We move all terms to the left:

2(x+1)-(6(x-3)-8)=0

We multiply parentheses

2x-(6(x-3)-8)+2=0



We calculate terms in parentheses: -(6(x-3)-8), so:

6(x-3)-8

We multiply parentheses

6x-18-8

We add all the numbers together, and all the variables

6x-26

Back to the equation:

-(6x-26)



We get rid of parentheses

2x-6x+26+2=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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