17-3(z-2)-11z=7(z+2)+9

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Solution for 17-3(z-2)-11z=7(z+2)+9 equation: 



17-3(z-2)-11z=7(z+2)+9

We move all terms to the left:

17-3(z-2)-11z-(7(z+2)+9)=0

We add all the numbers together, and all the variables

-11z-3(z-2)-(7(z+2)+9)+17=0

We multiply parentheses

-11z-3z-(7(z+2)+9)+6+17=0



We calculate terms in parentheses: -(7(z+2)+9), so:

7(z+2)+9

We multiply parentheses

7z+14+9

We add all the numbers together, and all the variables

7z+23

Back to the equation:

-(7z+23)



We add all the numbers together, and all the variables

-14z-(7z+23)+23=0

We get rid of parentheses

-14z-7z-23+23=0

We add all the numbers together, and all the variables

-21z=0

z=0/-21

z=0

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