((n+1)/8)-((2-n)/3)=5/6

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Solution for ((n+1)/8)-((2-n)/3)=5/6 equation: 



((n+1)/8)-((2-n)/3)=5/6

We move all terms to the left:

((n+1)/8)-((2-n)/3)-(5/6)=0

We add all the numbers together, and all the variables

((n+1)/8)-((-1n+2)/3)-(+5/6)=0

We get rid of parentheses

((n+1)/8)-((-1n+2)/3)-5/6=0

We calculate fractions


(((n+1)*3)*6)/()+(-((-1n+2)*8)*6)/()+()/()=0



We calculate terms in parentheses: +(((n+1)*3)*6)/(), so:

((n+1)*3)*6)/(

We multiply all the terms by the denominator


((n+1)*3)*6)



We calculate terms in parentheses: +((n+1)*3)*6), so:

(n+1)*3)*6

We multiply parentheses

6n+

We add all the numbers together, and all the variables

6n

Back to the equation:

+(6n)



Back to the equation:

+(6n)





We calculate terms in parentheses: +(-((-1n+2)*8)*6)/(), so:

-((-1n+2)*8)*6)/(

We multiply all the terms by the denominator


-((-1n+2)*8)*6)



We calculate terms in parentheses: -((-1n+2)*8)*6), so:

(-1n+2)*8)*6

We multiply parentheses

-6n+

We add all the numbers together, and all the variables

-6n

Back to the equation:

-(-6n)



We get rid of parentheses

6n

Back to the equation:

+(6n)



We add all the numbers together, and all the variables

12n+1=0

We move all terms containing n to the left, all other terms to the right

12n=-1

n=-1/12

n=-1/12

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