17(4y-3)=11(6y-5)

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Solution for 17(4y-3)=11(6y-5) equation: 



17(4y-3)=11(6y-5)

We move all terms to the left:

17(4y-3)-(11(6y-5))=0

We multiply parentheses

68y-(11(6y-5))-51=0



We calculate terms in parentheses: -(11(6y-5)), so:

11(6y-5)

We multiply parentheses

66y-55

Back to the equation:

-(66y-55)



We get rid of parentheses

68y-66y+55-51=0

We add all the numbers together, and all the variables

2y+4=0

We move all terms containing y to the left, all other terms to the right

2y=-4

y=-4/2

y=-2

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