20x+4+7x=3(3x+1)+4

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Solution for 20x+4+7x=3(3x+1)+4 equation:



20x+4+7x=3(3x+1)+4
We move all terms to the left:
20x+4+7x-(3(3x+1)+4)=0
We add all the numbers together, and all the variables
27x-(3(3x+1)+4)+4=0
We calculate terms in parentheses: -(3(3x+1)+4), so:
3(3x+1)+4
We multiply parentheses
9x+3+4
We add all the numbers together, and all the variables
9x+7
Back to the equation:
-(9x+7)
We get rid of parentheses
27x-9x-7+4=0
We add all the numbers together, and all the variables
18x-3=0
We move all terms containing x to the left, all other terms to the right
18x=3
x=3/18
x=1/6

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