16y-8(3y-6)=72

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Solution for 16y-8(3y-6)=72 equation: 



16y-8(3y-6)=72

We move all terms to the left:

16y-8(3y-6)-(72)=0

We multiply parentheses

16y-24y+48-72=0

We add all the numbers together, and all the variables

-8y-24=0

We move all terms containing y to the left, all other terms to the right

-8y=24

y=24/-8

y=-3

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