6(x-6)+2=8(8x+2)-12

Solution for 6(x-6)+2=8(8x+2)-12 equation:

6(x-6)+2=8(8x+2)-12

We move all terms to the left:

6(x-6)+2-(8(8x+2)-12)=0

We multiply parentheses

6x-(8(8x+2)-12)-36+2=0


We calculate terms in parentheses: -(8(8x+2)-12), so:

8(8x+2)-12

We multiply parentheses

64x+16-12

We add all the numbers together, and all the variables

64x+4

Back to the equation:

-(64x+4)


We add all the numbers together, and all the variables

6x-(64x+4)-34=0

We get rid of parentheses

6x-64x-4-34=0

We add all the numbers together, and all the variables

-58x-38=0

We move all terms containing x to the left, all other terms to the right

-58x=38

x=38/-58

x=-19/29