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16x^2-58x+30=0
a = 16; b = -58; c = +30;
Δ = b2-4ac
Δ = -582-4·16·30
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-58)-38}{2*16}=\frac{20}{32} =5/8 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-58)+38}{2*16}=\frac{96}{32} =3 $
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