16x2+4x-10=8+7x2

Solution for 16x2+4x-10=8+7x2 equation:

16x^2+4x-10=8+7x^2

We move all terms to the left:

16x^2+4x-10-(8+7x^2)=0

We get rid of parentheses

16x^2-7x^2+4x-8-10=0

We add all the numbers together, and all the variables

9x^2+4x-18=0

a = 9; b = 4; c = -18;
Δ = b2-4ac
Δ = 42-4·9·(-18)
Δ = 664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{664}=\sqrt{4*166}=\sqrt{4}*\sqrt{166}=2\sqrt{166}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-2\sqrt{166}}{2*9}=\frac{-4-2\sqrt{166}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+2\sqrt{166}}{2*9}=\frac{-4+2\sqrt{166}}{18}
$