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16x+6=27x^2
We move all terms to the left:
16x+6-(27x^2)=0
determiningTheFunctionDomain -27x^2+16x+6=0
a = -27; b = 16; c = +6;
Δ = b2-4ac
Δ = 162-4·(-27)·6
Δ = 904
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{904}=\sqrt{4*226}=\sqrt{4}*\sqrt{226}=2\sqrt{226}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{226}}{2*-27}=\frac{-16-2\sqrt{226}}{-54} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{226}}{2*-27}=\frac{-16+2\sqrt{226}}{-54} $
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