(3x-10)+(16x-19)=180

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Solution for (3x-10)+(16x-19)=180 equation: 



(3x-10)+(16x-19)=180

We move all terms to the left:

(3x-10)+(16x-19)-(180)=0

We get rid of parentheses

3x+16x-10-19-180=0

We add all the numbers together, and all the variables

19x-209=0

We move all terms containing x to the left, all other terms to the right

19x=209

x=209/19

x=11

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