16x+10-2(8x)=3(8x+4)+2(-12x-1)

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Solution for 16x+10-2(8x)=3(8x+4)+2(-12x-1) equation: 



16x+10-2(8x)=3(8x+4)+2(-12x-1)

We move all terms to the left:

16x+10-2(8x)-(3(8x+4)+2(-12x-1))=0

We add all the numbers together, and all the variables

-12x-(3(8x+4)+2(-12x-1))+10=0



We calculate terms in parentheses: -(3(8x+4)+2(-12x-1)), so:

3(8x+4)+2(-12x-1)

We multiply parentheses

24x-24x+12-2

We add all the numbers together, and all the variables

10

Back to the equation:

-(10)



We add all the numbers together, and all the variables

-12x=0

x=0/-12

x=0

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