3(9-12x)=11-8(3x+4)

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Solution for 3(9-12x)=11-8(3x+4) equation: 



3(9-12x)=11-8(3x+4)

We move all terms to the left:

3(9-12x)-(11-8(3x+4))=0

We add all the numbers together, and all the variables

3(-12x+9)-(11-8(3x+4))=0

We multiply parentheses

-36x-(11-8(3x+4))+27=0



We calculate terms in parentheses: -(11-8(3x+4)), so:

11-8(3x+4)

determiningTheFunctionDomain
-8(3x+4)+11

We multiply parentheses

-24x-32+11

We add all the numbers together, and all the variables

-24x-21

Back to the equation:

-(-24x-21)



We get rid of parentheses

-36x+24x+21+27=0

We add all the numbers together, and all the variables

-12x+48=0

We move all terms containing x to the left, all other terms to the right

-12x=-48

x=-48/-12

x=+4

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