16x(2)+60x-100=0

Solution for 16x(2)+60x-100=0 equation:

16x(2)+60x-100=0

We add all the numbers together, and all the variables

16x^2+60x-100=0

a = 16; b = 60; c = -100;
Δ = b2-4ac
Δ = 602-4·16·(-100)
Δ = 10000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10000}=100$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-100}{2*16}=\frac{-160}{32}
=-5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+100}{2*16}=\frac{40}{32}
=1+1/4
$