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16t*t+23t+8=0
We add all the numbers together, and all the variables
23t+16t*t+8=0
Wy multiply elements
16t^2+23t+8=0
a = 16; b = 23; c = +8;
Δ = b2-4ac
Δ = 232-4·16·8
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-\sqrt{17}}{2*16}=\frac{-23-\sqrt{17}}{32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+\sqrt{17}}{2*16}=\frac{-23+\sqrt{17}}{32} $
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