(4x)(4x)+16x-22=3

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Solution for (4x)(4x)+16x-22=3 equation: 



(4x)(4x)+16x-22=3

We move all terms to the left:

(4x)(4x)+16x-22-(3)=0

We add all the numbers together, and all the variables

16x+4x4x-25=0

We move all terms containing x to the left, all other terms to the right

16x+4x4x=25

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