16t(16-t)=160

Solution for 16t(16-t)=160 equation:

16t(16-t)=160

We move all terms to the left:

16t(16-t)-(160)=0

We add all the numbers together, and all the variables

16t(-1t+16)-160=0

We multiply parentheses

-16t^2+256t-160=0

a = -16; b = 256; c = -160;
Δ = b2-4ac
Δ = 2562-4·(-16)·(-160)
Δ = 55296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{55296}=\sqrt{9216*6}=\sqrt{9216}*\sqrt{6}=96\sqrt{6}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(256)-96\sqrt{6}}{2*-16}=\frac{-256-96\sqrt{6}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(256)+96\sqrt{6}}{2*-16}=\frac{-256+96\sqrt{6}}{-32}
$