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6m^2-5m=1
We move all terms to the left:
6m^2-5m-(1)=0
a = 6; b = -5; c = -1;
Δ = b2-4ac
Δ = -52-4·6·(-1)
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-7}{2*6}=\frac{-2}{12} =-1/6 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+7}{2*6}=\frac{12}{12} =1 $
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