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16n^2-16n=480
We move all terms to the left:
16n^2-16n-(480)=0
a = 16; b = -16; c = -480;
Δ = b2-4ac
Δ = -162-4·16·(-480)
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{30976}=176$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-176}{2*16}=\frac{-160}{32} =-5 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+176}{2*16}=\frac{192}{32} =6 $
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